Q51 · CSIR NET Chemistry, December 2017
Paper: CSIR NET December 2017 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Oxidative Addition Reductive Elimination · Marks: 2 · Difficulty: Medium
In the complex $[\mathrm{Pd(L\text{-}L)(Me)(Ph)}]$, the bisphosphine (L-L) that does not allow reductive elimination of PhMe is
(a)
(b)
(c)
(d)
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
Reductive elimination needs Me and Ph cis. The helicene-backbone diphosphine (d) is a wide-bite, trans-spanning ligand that holds Me and Ph trans, so PhMe cannot be eliminated.
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