Q121 · CSIR NET Chemistry, December 2019
Paper: CSIR NET December 2019 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Marks: 2 · Difficulty: Hard
The concentration $(\mathrm{C})$ of a compound undergoing decomposition as a function of time $(\mathrm{t})$ is given below:
The order of the reaction is Options:
| t/min | 0 | 1 | 2 | 4 | 6 |
|---|---|---|---|---|---|
| C/M | 1.00 | 0.80 | 0.67 | 0.50 | 0.40 |
(a)0
(b)1
(c)2
(d)3
Answer
Answer: C ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
1/C = 1.00, 1.25, 1.49, 2.00, 2.50 at t = 0, 1, 2, 4, 6 min — linear in t with slope 0.25 M⁻¹ min⁻¹, so the reaction is second order (option 2).
Study loop for Chemical Kinetics