Q36 · CSIR NET Chemistry, December 2019
Paper: CSIR NET December 2019 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Marks: 2 · Difficulty: Hard
The oxidation of NO to $\mathrm{NO_2}$ occurs via the mechanism given below.
$\mathrm{2NO \underset{k_{-1}}{\overset{k_1}{\rightleftharpoons}} N_2O_2}$; $\mathrm{N_2O_2 + O_2 \xrightarrow{k_2} 2NO_2}$
$\frac{d[\mathrm{NO_2}]}{dt}$ in the presence of large excess of $\mathrm{O_2}$ can be written as(a)$2k_1(\mathrm{NO})^2$
(b)$2k_1k_2(\mathrm{NO})^2(\mathrm{O_2})$
(c)$\frac{k_1}{k_2}(\mathrm{NO})^2$
(d)$2k_2(\mathrm{NO})^2$
Answer
Answer (as printed): A
Explanation
No explanation was printed for this question.
Study loop for Chemical Kinetics