Q51 · CSIR NET Chemistry, December 2019
Paper: CSIR NET December 2019 · Subject: Physical Chemistry · Chapter: Surface Chemistry · Topic: Catalysis Surface · Marks: 2 · Difficulty: Hard
The order of a surface catalyzed unimolecular reaction, at very low and very high pressures of the reactant, would be, respectively
(a)0,0
(b)1,0
(c)0,1
(d)1,1
Answer
Answer (as printed): B
Explanation
𝑘𝑃 𝜃= 1 + kP At very low pressure, Kp << 1; 𝜃 = kP (first order) At very high pressure kP>>1; 𝜃 =1 (zero order) CSIR NOV 2020
Explanation as extracted from the printed page; notation may be imperfect.
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