Q1 · CSIR NET Chemistry, June 2011
Paper: CSIR NET June 2011 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Easy
The highest occupied MO in $N_2$ and $O_2^+$ respectively are (take x-axis as internuclear axis)
(a)$\sigma_{2p_x},\ \pi^*_{2p_y}$
(b)$\pi_{2p_y},\ \pi_{2p_z}$
(c)$\sigma^*_{2p_x},\ \sigma_{2p_x}$
(d)$\pi^*_{2p_y},\ \pi^*_{2p_z}$
Answer
Answer (as printed): A
Explanation
Taking x-axis as internuclear axis. N2 = σ21s σ21s* σ22s σ22s* π22py π22pz σ22px O2+ = σ21s σ21s* σ22s σ22s* π22px π22py σ22px π1*2pz π1*2py
Explanation as extracted from the printed page; notation may be imperfect.
Study loop for Chemical Bonding