Q62 · CSIR NET Chemistry, June 2011
Paper: CSIR NET June 2011 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Medium
Match list I (compounds) with list II (structures), and select the correct answer using the codes given below.
| List - I | List- II |
|---|---|
| (a) $\mathrm{XeO_4}$ | (I) Square planar |
| (b) $\mathrm{BrF_4^{-}}$ | (ii) Tetrahedral |
| (c) $\mathrm{SeCl_4}$ | (iii) Distorted tetrahedral |
(a)(A-ii) (B-iii) (C-i)
(b)(A-iii) (B-i) (C-ii)
(c)(A-ii) (B-i) (C-iii)
(d)(A-i) (B-ii) (C-iii)
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
XeO₄ is tetrahedral, BrF₄⁻ square planar (2 lone pairs) and SeCl₄ see-saw, i.e. distorted tetrahedral (c).
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