Q21 · CSIR NET Chemistry, June 2012
Paper: CSIR NET June 2012 · Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Statistical Thermodynamics – General · Marks: 2 · Difficulty: Medium
The correct entropy for 6 identical particles with their occupation number $0,1,2,3$ in four steps is :
(a)$k_{A} \ln 8$
(b)$k_{A} \ln 12$
(c)$k_{B} \ln 60$
(d)$k_{B} \ln 720$
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
W = 6!/(0!1!2!3!) = 60, so S = k_B ln 60 (c).
Study loop for Statistical Thermodynamics