Q37 · CSIR NET Chemistry, June 2015
Paper: CSIR NET June 2015 · Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acids & Bases – General · Marks: 2 · Difficulty: Medium
Match the action of $\mathrm{H}_{2} \mathrm{O}_{2}$, in aqueous medium given in column A with the oxidation/reduction listed in column B
The correct answer is
| A: action of $\mathrm{H_2O_2}$ | B: type of reaction |
|---|---|
| (1) Oxidation in acid | (A) $[\mathrm{Fe(CN)_6}]^{3-} \rightarrow [\mathrm{Fe(CN)_6}]^{4-}$ |
| (II) Oxidation in base | (B) $[\mathrm{Fe(CN)_6}]^{4-} \rightarrow [\mathrm{Fe(CN)_6}]^{3-}$ |
| (III) Reduction in acid | (C) $\mathrm{MnO_4^{-}} \rightarrow \mathrm{Mn^{2+}}$ |
| (IV) Reduction in base | (D) $\mathrm{Mn^{2+}} \rightarrow \mathrm{Mn^{4+}}$ |
(a)I-A, II-B, III-C, IV-D
(b)I-B, II-D, III-C, IV-A
(c)I-C, II-D, III-B, IV-A
(d)I-D, II-A, III-C, IV-B
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
H₂O₂ oxidises [Fe(CN)₆]⁴⁻ to [Fe(CN)₆]³⁻ in acid, and Mn²⁺ to MnO₂ (Mn⁴⁺) in base. It reduces MnO₄⁻ to Mn²⁺ in acid, and [Fe(CN)₆]³⁻ to [Fe(CN)₆]⁴⁻ in base. I-B, II-D, III-C, IV-A (b).
Study loop for Acids and Bases