Q46 · CSIR NET Chemistry, June 2015
Paper: CSIR NET June 2015 · Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Electron Transfer Redox · Marks: 2 · Difficulty: Medium
The lowest energy-state of an atom with electronic configuration $ns^{1}np^{1}$ has the term symbol
(a)$^{3}P_{1}$
(b)$^{1}P_{1}$
(c)$^{3}P_{2}$
(d)$^{3}P_{0}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
ns¹np¹: triplet lies lowest (Hund), and with a less-than-half-filled shell the smallest J is lowest: ³P₀.
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