Q50 · CSIR NET Chemistry, June 2015
Paper: CSIR NET June 2015 · Subject: Inorganic Chemistry · Chapter: Inorganic Spectroscopy · Topic: Inorganic Spectroscopy – General · Marks: 2 · Difficulty: Medium
The $^{119}\mathrm{Sn}$ NMR chemical shift (approximately in ppm) corresponding to $(\eta^{5}\text{-}\mathrm{Cp})_{2}\mathrm{Sn}$ (relative to $\mathrm{Me_4Sn}$) is
(a)-4
(b)+137
(c)+346
(d)-2200
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
Stannocene appears near −2200 ppm (d).
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