Q27 · CSIR NET Chemistry, June 2016
Paper: CSIR NET June 2016 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Easy
Correct combination for $\pi$ and $\pi^{*}$ orbitals in $\mathrm{B_2}$ molecule is
(a)$\pi$: Gerade, $\pi^{*}$: Ungerade
(b)$\pi$: Ungerade, $\pi^{*}$: Gerade
(c)$\pi$: Gerade, $\pi^{*}$: Gerade
(d)$\pi$: Ungerade, $\pi^{*}$: Ungerade
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
For a homonuclear diatomic the bonding π orbital is π_u (ungerade) and the antibonding π* is π_g (gerade).
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