Q56 · CSIR NET Chemistry, June 2016
Paper: CSIR NET June 2016 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Marks: 2 · Difficulty: Hard
If the rates of a reaction are $R_1$ and $R_2$ at concentrations $C_1$ and $C_2$ of a reactant respectively, the order of reaction, 'n' (assuming that the concentrations of all other reactants and T remain constant) with respect to that reactant is given by
(a)$n = \frac{\log R_1 - \log R_2}{\log C_1 - \log C_2}$
(b)$n = \frac{\log C_1 - \log C_2}{\log R_1 - \log R_2}$
(c)$n = \frac{\log C_1 - \log R_1}{\log C_2 - \log R_2}$
(d)$n = \frac{\log C_2 - \log R_2}{\log C_1 - \log R_1}$
Answer
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Explanation
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