Q14 · CSIR NET Chemistry, June 2017
Paper: CSIR NET June 2017 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Nernst Cells · Marks: 2 · Difficulty: Medium
A solution of $\mathrm{Fe}^{3+}$ is titrated potentiometrically using $\mathrm{Ce}^{3+}$ solution at $25\,^{\circ}\mathrm{C}$. The emf (in V) of the redox system thus formed when, (i) $50\%$ of $\mathrm{Fe}^{3+}$ and (ii) $80\%$ of $\mathrm{Fe}^{3+}$ are titrated, would respectively be (Given $E^{o}_{\mathrm{Fe}^{3+}/\mathrm{Fe}^{2+}}=0.77\,\mathrm{V}$, $\log 2=0.301$)
(a)0.734 and 0.77
(b)0.77 and 0.385
(c)0.77 and 0.734
(d)0.385 and 0.367
Answer
Answer (as printed): C
Explanation
No explanation was printed for this question.
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