Q42 · CSIR NET Chemistry, June 2017
Paper: CSIR NET June 2017 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Oxidative Addition Reductive Elimination · Marks: 2 · Difficulty: Medium
Reaction of $\mathrm{Na[Mn(CO)_5]}$ with $\mathrm{H_3C=CHCH_2Cl}$ gives A along with NaCl. Photolysis of compound A results in compound B together with elimination of CO. The correct structural formulations of compounds A and B are respectively,
(a)
B
B(b)
B
BAnswer
Answer: A ✓ checked by 4AB · confidence high
Explanation
[Mn(CO)₅]⁻ displaces Cl⁻ to give σ-allyl (η¹-CH₂CH=CH₂)Mn(CO)₅ (A). Photolysis expels CO and the allyl becomes η³: (η³-C₃H₅)Mn(CO)₄ (B) (a).
Study loop for Organometallic Compounds