Q23 · CSIR NET Chemistry, June 2018
Paper: CSIR NET June 2018 · Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acids & Bases – General · Marks: 2 · Difficulty: Medium
The transformation are given in Column 1 and reagent in Column II. Match the items of Column I with those of Column II
| Column I | ColumnII |
|---|---|
| (a) $[\mathrm{MnO_4}]^{-} \rightarrow [\mathrm{MnO_4}]^{2-}$ | (i) $\mathrm{H_2SO_4}$ |
| (b) $\mathrm{Me_3CH} \rightarrow [\mathrm{Me_3C}]^{+}$ | (ii) Na in liquid $\mathrm{NH_3}$ |
| (c) $\mathrm{Ag+Au} \rightarrow [\mathrm{AuF_4}]$ | (iii) $[\mathrm{H_2SO_4F}]^{+}$ (super acid) |
| (d) $\mathrm{H_3PO_4} \rightarrow [\mathrm{P(OH)_4}]^{+}$ | (iv) Liquid $\mathrm{BrF_3}$ |
(a)(a)-(i); (b)-(ii); (c)-(iii); (d)-(iv)
(b)(a)-(ii); (b)-(iii); (c)-(iv); (d)-(i)
(c)(a)-(iii); (b)-(ii); (c)-(i); (d)-(iv)
(d)(a)-(iii); (b)-(i); (c)-(iv); (d)-(ii)
Answer
Answer: B ✓ checked by 4AB · confidence medium
The source book printed C; on checking, B is correct — see the explanation.
Explanation
(a) MnO₄⁻ → MnO₄²⁻ is a one-electron reduction (Na/NH₃). (b) The superacid abstracts hydride from Me₃CH, giving the t-Bu⁺ cation. (c) BrF₃ fluorinates Ag + Au to Ag[AuF₄]. (d) H₂SO₄ protonates H₃PO₄ to P(OH)₄⁺ (b).
Study loop for Acids and Bases