Q35 · CSIR NET Chemistry, June 2018
Paper: CSIR NET June 2018 · Subject: Inorganic Chemistry · Chapter: Coordination Chemistry · Topic: Electron Transfer Redox · Marks: 2 · Difficulty: Medium
The lowest energy state of a $1s^{1}2s^{1}$ electronic configuration, according to hund's rule, is
(a)$^{3}S_{0}$
(b)$^{1}S_{0}$
(c)$^{3}S_{1}$
(d)$^{1}S_{1}$
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
1s¹2s¹: the triplet lies lowest (Hund), L = 0, J = 1 → ³S₁.
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