Q3 · CSIR NET Chemistry, June 2019
Paper: CSIR NET June 2019 · Subject: Inorganic Chemistry · Chapter: Acid and Bases · Topic: Acid and Bases – General · Marks: 2 · Difficulty: Medium
The cations formed upon dissolving $\mathrm{SnF}_{4}$ and $\mathrm{AuF}_{3}$ in liquid $\mathrm{BrF}_{3}$ separately, respectively are
(a)$\mathrm{SnF}_{3}^{+}$ and $\mathrm{BrF}_{2}^{+}$
(b)$\mathrm{BrF}_{2}^{+}$ and $\mathrm{AuF}_{2}^{+}$
(c)$\mathrm{BrF}_{2}^{+}$ only
(d)$\mathrm{SnF}_{3}^{+}$ and $\mathrm{AuF}_{2}^{+}$
Answer
Answer (as printed): C
Explanation
2BrF3 + SnF4 →(BrF2)2[SnF6] Species formed in reaction are BrF2+ and [SnF6]-2 AuF3 + BrF3 → BrF2+[AuF4]- Species formed in reaction are BrF2+ and [AuF4]- CSIR DEC 2019
Explanation as extracted from the printed page; notation may be imperfect.
Study loop for Acid and Bases