Q121 · CSIR-NET Chemistry, December 2013
Paper: CSIR-NET December 2013 · Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Partial Molar Quantities · Marks: 2 · Difficulty: Easy
The chemical potential $\left(\mu_{\mathrm{i}}\right)$ of the $\mathrm{i}^{\text {th }}$ component is defined as
(a)$\mu_{\mathrm{i}}=\left(\frac{\partial \mathrm{U}}{\partial \mathrm{n}_{\mathrm{i}}}\right)_{\mathrm{T}, \mathrm{P}}$
(b)$\mu_{\mathrm{i}}=\left(\frac{\partial \mathrm{H}}{\partial \mathrm{n}_{\mathrm{i}}}\right)_{\mathrm{T}, \mathrm{P}}$
(c)$\mu_{\mathrm{i}}=\left(\frac{\partial \mathrm{A}}{\partial \mathrm{n}_{\mathrm{i}}}\right)_{\mathrm{T}, \mathrm{P}}$
(d)$\mu_{\mathrm{i}}=\left(\frac{\partial \mathrm{G}}{\partial \mathrm{n}_{\mathrm{i}}}\right)_{\mathrm{T}, \mathrm{P}}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
At constant T and P, μ_i = (∂G/∂n_i)_{T,P,n_j}; the U, H and A derivatives give μ_i only at their own natural variables.
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