Q122 · CSIR-NET Chemistry, December 2013
Paper: CSIR-NET December 2013 · Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Thermodynamics – General · Marks: 2 · Difficulty: Medium
Work (w) involved in isothermal reversible expansion from $\mathrm{V}_{\mathrm{i}}$ to $\mathrm{V}_{\mathrm{f}}$ of n moles of an ideal gas is
(a)$\mathrm{w}=-\mathrm{nRT} \ln \left(\mathrm{V}_{\mathrm{f}} / \mathrm{V}_{\mathrm{i}}\right)$
(b)$\mathrm{w}=\mathrm{nRT} \ln \left(\mathrm{V}_{\mathrm{f}} / \mathrm{V}_{\mathrm{i}}\right)$
(c)$\mathrm{w}=-\mathrm{nRT}\left(\mathrm{V}_{\mathrm{f}} / \mathrm{V}_{\mathrm{i}}\right)$
(d)$\mathrm{w}=-\mathrm{nRT} \log \left(\mathrm{Vf}_{\mathrm{f}} / \mathrm{V}_{\mathrm{i}}\right)$
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
w = −∫p dV = −nRT ln(V_f/V_i).
Study loop for Thermodynamics
· Browse this chapter in the app