In the following transformation, the reagent A and the major product B, respectively, are$\xrightarrow{\ \text{A}\ }$→ B
(a)and
(b)and
(c)and
(d)and
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
m-CPBA (A) gives the pyridine N-oxide. In the Boekelheide rearrangement with Ac₂O the 2-methyl group, which is α to the N-oxide, becomes CH₂OAc, giving 3-methyl-2-(acetoxymethyl)pyridine (d).
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