Q71 · CSIR-NET Chemistry, December 2013

Paper: CSIR-NET December 2013 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Cluster Compounds Wade Rules · Marks: 2 · Difficulty: Medium

Among the following clusters,
\[ \mathrm{A}=\left[(\mathrm{H}) \mathrm{Co}_{6}(\mathrm{CO})_{15}\right] \mathrm{B}=\left[(\mathrm{H})_{2} \mathrm{Os}_{6}(\mathrm{CO})_{18}\right] \mathrm{C}=\left[(\mathrm{H})_{2} \mathrm{Os}_{5}(\mathrm{CO})_{16}\right] \]
H is encapsulated in
(a)A only
(b)B only
(c)B and C only
(d)A and B only
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
[HCo₆(CO)₁₅]⁻ has an interstitial hydride at the centre of the Co₆ octahedron; in H₂Os₆(CO)₁₈ and H₂Os₅(CO)₁₆ the hydrides bridge edges/faces on the surface.

Study loop for Organometallic Compounds

1. Practise the PYQsPrevious-year questions, with answers

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