Q72 · CSIR-NET Chemistry, December 2013
Paper: CSIR-NET December 2013 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Cluster Compounds Wade Rules · Marks: 2 · Difficulty: Medium
The correct statement regarding terminal/bridging CO groups in solid $mathrm{Co_4(CO)_{12}}$ and $mathrm{Ir_4(CO)_{12}}$ is
(a)both have equal number of bridging CO groups
(b)number of bridging CO groups in $mathrm{Co_4(CO)_{12}}$ is 4
(c)the number of terminal CO groups in $mathrm{Co_4(CO)_{12}}$ is 8
(d)the number of bridging CO groups in $mathrm{Ir_4(CO)_{12}}$ is zero.
Answer
Answer: D ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
Co₄(CO)₁₂ has three edge-bridging CO on the basal Co₃ face and nine terminal CO; Ir₄(CO)₁₂ (larger metal) has all twelve CO terminal, none bridging.
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