For an enzyme-substrate reaction, a plot between $1 / \mathrm{v}$ and $1 /\left[\mathrm{S}_{0}\right]$ yields a slope of 40 s . If the enzyme concentration is $2.5 \mu \mathrm{M}$, then the catalytic efficiency of the enzyme is
(a)$40 \mathrm{Lmol}^{-1} \mathrm{s}^{-1}$
(b)$10^{-4} \mathrm{Lmol}^{-1} \mathrm{s}^{-1}$
(c)$10^{7} \mathrm{Lmol}^{-1} \mathrm{s}^{-1}$
(d)$10^{4} \mathrm{Lmol}^{-1} \mathrm{s}^{-1}$
Answer
Answer: D ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.