Q22 · CSIR-NET Chemistry, December 2015

Paper: CSIR-NET December 2015 · Subject: Organic Chemistry · Chapter: Reagents, Reaction Mechanisms & Named Reactions · Topic: Reagents, Reaction Mechanisms & Named Reactions – General · Marks: 2 · Difficulty: Medium

Under review — part of this question (a structure or an option) is not clear in the source scan. 4AB is checking it against the original book; the answer shown may change.
The major structures of A and B in the following reaction sequence are Question structure 1 of 5, ABC26OR0281 Question structure 2 of 5, ABC26OR0281 Question structure 3 of 5, ABC26OR0281 Question structure 4 of 5, ABC26OR0281 Question structure 5 of 5, ABC26OR0281
(a)Option (a) structure 1 of 4, ABC26OR0281 Option (a) structure 2 of 4, ABC26OR0281 Option (a) structure 3 of 4, ABC26OR0281 Option (a) structure 4 of 4, ABC26OR0281
(b)Option (b) structure 1 of 4, ABC26OR0281 Option (b) structure 2 of 4, ABC26OR0281 Option (b) structure 3 of 4, ABC26OR0281 Option (b) structure 4 of 4, ABC26OR0281
(c)Option (c) structure 1 of 4, ABC26OR0281 Option (c) structure 2 of 4, ABC26OR0281 Option (c) structure 3 of 4, ABC26OR0281 Option (c) structure 4 of 4, ABC26OR0281
(d)Option (d) structure 1 of 3, ABC26OR0281 Option (d) structure 2 of 3, ABC26OR0281 B = Option (d) structure 3 of 3, ABC26OR0281
Answer
Under review — not yet confirmed.
Answer: D

The source book printed C; on checking, D is correct — see the explanation.

Explanation
NaH forms the naphthoxide, which displaces chloride to give the glycidyl ether A with the epoxide configuration intact; isopropylamine then attacks the terminal epoxide carbon, so the carbinol centre is untouched — propranolol with the OH drawn as in the epoxide (d).

Study loop for Reagents, Reaction Mechanisms & Named Reactions

1. Practise the PYQsPrevious-year questions, with answers

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