Q23 · CSIR-NET Chemistry, December 2015

Paper: CSIR-NET December 2015 · Subject: Organic Chemistry · Chapter: Reagents, Reaction Mechanisms & Named Reactions · Topic: Reagents, Reaction Mechanisms & Named Reactions – General · Marks: 2 · Difficulty: Medium

The major structures of A and B in the following reaction sequence are Question structure 1 of 6, ABC26OR0282 Question structure 2 of 6, ABC26OR0282 Question structure 3 of 6, ABC26OR0282 Question structure 4 of 6, ABC26OR0282 Question structure 5 of 6, ABC26OR0282 Question structure 6 of 6, ABC26OR0282
(a)Option (a) structure 1 of 3, ABC26OR0282 Option (a) structure 2 of 3, ABC26OR0282 B = Option (a) structure 3 of 3, ABC26OR0282
(b)Option (b) structure 1 of 3, ABC26OR0282 Option (b) structure 2 of 3, ABC26OR0282 B = Option (b) structure 3 of 3, ABC26OR0282
(c)A = Option (c) structure 1 of 2, ABC26OR0282 B = Option (c) structure 2 of 2, ABC26OR0282
(d)A = Option (d) structure 1 of 2, ABC26OR0282 Option (d) structure 2 of 2, ABC26OR0282
Answer
Answer: B ✓ checked by 4AB · confidence medium
Explanation
Semicarbazide condenses with the enone C=O through its terminal hydrazinic NH₂. This gives the semicarbazone R₂C=N–NH–CO–NH₂ (A as drawn in (b); option (a) shows the wrong connectivity, H₂N–NH–CO–N=). Heating with t-BuOK in diglyme/t-BuOH is a Wolff–Kishner reduction, which turns the C=N carbon into CH₂ and gives the octalin B. B is drawn the same in (a) and (b), so the A structure decides the answer: (b).

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