Q100 · CSIR-NET Chemistry, December 2016

Paper: CSIR-NET December 2016 · Subject: Physical Chemistry · Chapter: Molecular Spectroscopy · Topic: Molecular Spectroscopy – General · Marks: 2 · Difficulty: Medium

In a 200 MHz NMR spectrometer, a molecule shows two doublets separated by 2 ppm. The observed coupling constant is 10 Hz. The separation between these two signals and the coupling constant in a 600 MHz spectrometer will be, respectively
(a)600 Hz and 30 Hz
(b)1200 Hz and 30 Hz
(c)600 Hz and 10 Hz
(d)1200 Hz and 10 Hz
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
1200 Hz and 10 Hz (d).

Study loop for Molecular Spectroscopy

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