The expected number of ${}^{19}\mathrm{F}$ NMR spectral lines, including satellites, for $\mathrm{[XeF_5]^-}$ is [Abundance of ${}^{129}\mathrm{Xe}\,(\mathrm{I}=1/2)=26\%$ ]
(a)two
(b)twenty one
(c)three
(d)one
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
The five F of [XeF₅]⁻ are equivalent: a central singlet (74 %, non-magnetic Xe) flanked by a ¹²⁹Xe satellite doublet — three lines (c).