Q55 · CSIR-NET Chemistry, December 2016
Paper: CSIR-NET December 2016 · Subject: Inorganic Chemistry · Chapter: Inorganic Spectroscopy · Topic: Inorganic Spectroscopy – General · Marks: 2 · Difficulty: Hard
The reaction between $\mathrm{PI_3}$, $\mathrm{PSCl_3}$ and zinc powder gives $\mathrm{P_3I_5}$ as one of the products. The solution state $^{31}\mathrm{P}$ NMR spectrum of $\mathrm{P_3I_5}$ shows a doublet ($\delta$ 98) and a triplet ($\delta$ 102). The correct structure of $\mathrm{P_3I_5}$ is
(a)
(b)
(c)
(d)
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
I₂P–P(I)–PI₂: the two equivalent terminal P atoms couple to one central P (doublet), and the central P couples to two terminal P (triplet) (c).
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