For complex A, deuteration of NH protons does not alter the EPR spectrum. The number of hyper fine lines expected in the EPR $\left[\mathrm{I}\left({ }^{63} \mathrm{Cu}\right)=3 / 2\right]$ spectrum of A is
(a)20
(b)12
(c)60
(d)36
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
Deuterating the NH protons changes nothing, so no ¹H superhyperfine is resolved. ⁶³Cu (4 lines) × two equivalent ¹⁴N (5 lines) = 20 (a).