Q47 · CSIR-NET Chemistry, December 2018
Paper: CSIR-NET December 2018 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Marks: 2 · Difficulty: Medium
The product for the reaction given below is $\mathrm{IrCl(COE)(PMe_3)_3}$ (COE = Cyclooctene) $+$ 
$\rightarrow$
$\rightarrow$(a)
(b)
(c)
(d)
Answer
Answer: A ✓ checked by 4AB · confidence medium
The source book printed B; on checking, A is correct — see the explanation.
Explanation
Ir(I) inserts into the epoxide and isomerises it to the hydrido-acetonyl Ir(III) complex IrH(Cl)(CH₂COCH₃)(PMe₃)₃ (Milstein). Option (b) needs a second Cl that is not available (a).
Study loop for Organometallic Compounds