For a van der Waals gas, the partial derivative is ((∂ U)/(∂ V))T

Q158 · CSIR-NET Chemistry, December 2019

Paper: CSIR-NET December 2019 · Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Thermodynamics – General · Marks: 2 · Difficulty: Easy

For a van der Waals gas, the partial derivative is $\left(\frac{\partial \mathrm{U}}{\partial \mathrm{V}}\right)_{\mathrm{T}}$

(a)$\frac{\mathrm{V}_{\mathrm{m}}}{\mathrm{a}}$

(b)$\frac{\mathrm{V}_{\mathrm{m}}^{2}}{\mathrm{a}}$

(c)$\frac{\mathrm{a}}{\mathrm{V}_{\mathrm{m}}^{2}}$

(d)$\frac{\mathrm{a}}{\mathrm{V}_{\mathrm{m}}}$

Answer

Answer: C ✓ checked by 4AB · confidence high

Explanation

Internal pressure of a van der Waals gas: (∂U/∂V)_T = a/V_m².

Study loop for Thermodynamics