Q159 · CSIR-NET Chemistry, December 2019

Paper: CSIR-NET December 2019 · Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Partial Molar Quantities · Marks: 2 · Difficulty: Medium

The change in chemical potential (in J ) of one mole of an ideal gas, when it is compressed isothermally at 300 K from 1.0 atm to 2.0 atm , is closest to $(\ln 2=0.69)$ Options:

(a)1225

(b)1725

(c)2425

(d)2725

Answer

Answer: B ✓ checked by 4AB · confidence high

The source book printed C; on checking, B is correct — see the explanation.

Explanation

Δμ = RT ln(p₂/p₁) = 8.314 × 300 × 0.69 = 1721 J ≈ 1725 J.

Study loop for Thermodynamics

1. Practise the PYQsPrevious-year questions, with answers

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