4AB › Chemistry PYQ › CSIR-NET › June 2011 › Q1Q1 · CSIR-NET Chemistry, June 2011 Paper: CSIR-NET June 2011 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Easy
The highest occupied MO in $\mathrm{N_2}$ and $\mathrm{O_2^{+}}$ respectively are (take x-axis as internuclear axis)
(a) $\sigma_{2px}$ , $\pi^{*}_{2py}$
(b) $\pi_{2 \mathrm{py}}, \pi_{2 \mathrm{pz}}$
(c) $\sigma^{*}{ }_{2 p x}, \sigma_{2 p x}$
(d) $\pi^{*}{ }_{2 \mathrm{py}}, \pi^{*}{ }_{2 \mathrm{pz}}$
Answer Answer: A ✓ checked by 4AB · confidence high
Explanation With x as the bond axis, the HOMO of N₂ is σ2pₓ (s–p mixing raises it above π); O₂⁺ has one electron in π*2p — $\sigma_{2p_x}$ and $\pi^{*}_{2p_y}$ (a).
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