Q2 · CSIR-NET Chemistry, June 2011

Paper: CSIR-NET June 2011 · Subject: Inorganic Chemistry · Chapter: Inorganic Spectroscopy · Topic: Inorganic Spectroscopy – General · Marks: 2 · Difficulty: Medium

In the EPR spectrum of tetragonal Cu(II) complex, when $g_{\parallel} > g_{\perp} > g_{e}$, the unpaired electron resides in the orbital.
(a)$\mathrm{d}_{xy}$
(b)$\mathrm{d}_{x^{2}-y^{2}}$
(c)$\mathrm{d}_{z^{2}}$
(d)$\mathrm{d}_{xz}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
g∥ > g⊥ > ge for tetragonal Cu(II) indicates the unpaired electron in dx²−y² (b).

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