The relative rates of solvolysis of iodides A-C are
(a)C $>$ A $>$ B
(b)$\mathrm{C}>\mathrm{B}>\mathrm{A}$
(c)B $>$ C $>$ A
(d)B $>$ A $>$ C
Answer
Answer: A ✓ checked by 4AB · confidence medium
Explanation
The vinylic iodide B cannot ionise to a stabilised cation and is slowest. In the oxacyclooctyl iodide C the ring oxygen gives transannular (neighbouring-group) assistance, so C reacts faster than cyclooctyl iodide A: C > A > B (a).