Q83 · CSIR-NET Chemistry, June 2011

Paper: CSIR-NET June 2011 · Subject: Inorganic Chemistry · Chapter: Nuclear Chemistry · Topic: Nuclear Reactions Q Value · Marks: 2 · Difficulty: Easy

Consider the nuclear reaction
\[ { }_{92} \mathrm{X}^{234}+\beta+\alpha \rightarrow \mathrm{Y}+\gamma+2 \beta^{+} \]
Y is
(a)${ }_{92} \mathrm{Y}^{238}$
(b)${ }_{91} \mathrm{Y}^{238}$
(c)${ }_{93} \mathrm{Y}^{236}$
(d)${ }_{94} \mathrm{Y}^{238}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Mass: 234 + 4 = 238. Charge: 92 − 1 + 2 = Z(Y) + 2, so Z = 91. Y is ²³⁸₉₁Y (b).

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