Paper: CSIR-NET June 2011 · Subject: Inorganic Chemistry · Chapter: Nuclear Chemistry · Topic: Nuclear Reactions Q Value · Marks: 2 · Difficulty: Medium
The species ${ }^{19} \mathrm{Ne}$ and ${ }^{14} \mathrm{C}$ emit a positron and $\beta$-particle respectively. The resulting species formed are respectively
(a)${ }^{19} \mathrm{Na}$ and ${ }^{14} \mathrm{B}$
(b)${ }^{19} \mathrm{F}$ and ${ }^{14} \mathrm{N}$
(c)${ }^{19} \mathrm{Na}$ and ${ }^{14} \mathrm{N}$
(d)${ }^{19}\mathrm{F}$ and ${ }^{14}\mathrm{B}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Positron emission lowers Z by one: ¹⁹Ne → ¹⁹F; β⁻ emission raises it: ¹⁴C → ¹⁴N.