Q17 · CSIR-NET Chemistry, June 2012

Paper: CSIR-NET June 2012 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Medium

The molar conductivities at infinite dilution $\Lambda_{m}^{o}$ for $\mathrm{Na}_{2} \mathrm{SO}_{4}, \mathrm{K}_{2} \mathrm{SO}_{4}, \mathrm{KCl}, \mathrm{HCl}$ and HCOONa at 300 K are $260,308,150,426$ and $105 \mathrm{S} \mathrm{cm}^{-1} \mathrm{mol}^{-2}$ respectively. Hence $\Lambda_{m}^{o}$ for formic acid in the same unit and at the same temperature is
(a)381
(b)405
(c)429
(d)531
Answer
Answer: B ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation
Λ°(NaCl) = ½Λ°(Na₂SO₄) − ½Λ°(K₂SO₄) + Λ°(KCl) = 130 − 154 + 150 = 126. Then Λ°(HCOOH) = Λ°(HCOONa) + Λ°(HCl) − Λ°(NaCl) = 105 + 426 − 126 = 405.

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