Q12 · CSIR-NET Chemistry, June 2014

Paper: CSIR-NET June 2014 · Subject: Physical Chemistry · Chapter: Solid State Chemistry · Topic: Crystal Systems Lattices · Marks: 2 · Difficulty: Medium

The interplanar spacing of (110) planes in a cubic unit cell with lattice parameter $a=4.242$ Å is

(a)$3 \AA$

(b)$6 \AA$

(c)$7.35 \AA$

(d)$2.45 \AA$

Answer

Answer: A ✓ checked by 4AB · confidence high

Explanation

d_hkl = a/√(h² + k² + l²) = 4.242/√2 = 3.00 Å.

Study loop for Solid State Chemistry

1. Practise the PYQsPrevious-year questions, with answers

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