Q13 · CSIR-NET Chemistry, June 2014

Paper: CSIR-NET June 2014 · Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Statistical Equilibrium · Marks: 2 · Difficulty: Medium

The number of configurations in the most probable state, according to Boltzmann formula, is

(a)$e^{\frac{S}{k_{B}}}$

(b)$e^{\frac{-S}{k_{B}}}$

(c)$e^{\frac{-E}{k_{B} T}}$

(d)$e^{\frac{-\Delta G}{k_{B} T}}$

Answer

Answer: A ✓ checked by 4AB · confidence high

Explanation

Boltzmann: S = k_B ln W, so the number of configurations of the most probable state is W = e^{S/k_B}.

Study loop for Statistical Thermodynamics