Q27 · CSIR-NET Chemistry, June 2015

Paper: CSIR-NET June 2015 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Arrhenius Activation · Marks: 2 · Difficulty: Medium

The temperature-dependence of a reaction is given by $k=A T^{2} \exp \left(-E_{0} / R T\right)$ The activation energy Ea of the reaction is given by:
(a)$\mathrm{E}_{0}+\frac{1}{2} R T$
(b)$\mathrm{E}_{0}$
(c)$\mathrm{E}_{0}+2 \mathrm{RT}$
(d)$2 \mathrm{E}_{0}+\mathrm{RT}$
Answer
Answer: C ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation
Ea = RT²(d ln k/dT) = RT²(2/T + E₀/RT²) = E₀ + 2RT.

Study loop for Chemical Kinetics

1. Practise the PYQsPrevious-year questions, with answers

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