Q28 · CSIR-NET Chemistry, June 2015

Paper: CSIR-NET June 2015 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Marks: 2 · Difficulty: Medium

For a reaction, $2 A+B \rightarrow 3 Z$, if the rate of consumption of $A$ is $2 \times 10^{-4} \mathrm{mol} \mathrm{dm}^{-3} \mathrm{s}^{-1}$ the rate of formation of $\mathrm{Z}$ (in $\mathrm{mol ~ dm}^{-\mathrm{3}} \mathrm{s}^{-\mathrm{1}}$ ) will be
(a)$3 \times 10^{-4}$
(b)$2 \times 10^{-4}$
(c)$\frac{4}{3} \times 10^{-4}$
(d)$4 \times 10^{-4}$
Answer
Answer: A ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation
Rate = −½ d[A]/dt = ⅓ d[Z]/dt, so d[Z]/dt = (3/2) × 2×10⁻⁴ = 3×10⁻⁴ mol dm⁻³ s⁻¹.

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