Q29 · CSIR-NET Chemistry, June 2015

Paper: CSIR-NET June 2015 · Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Marks: 2 · Difficulty: Medium

In a photochemical reaction, radicals formed according to the equation
\[ \begin{array}{l} \mathrm{C_4H_{10}} + h\nu \rightleftharpoons 2\,\mathrm{C_2H_5} \\ \mathrm{C_2H_5} + \mathrm{C_2H_5} \xrightarrow{k_2} \mathrm{C_2H_6} + \mathrm{C_2H_4} \end{array} \]
If I is the intensity of light absorbed, the rate of the overall reaction is proportional to-
(a)I
(b)$\mathrm{I}^{1 / 2}$
(c)$I[\mathrm{C_4H_{10}}]$
(d)$I^{1/2}[\mathrm{C_4H_{10}}]^{1/2}$
Answer
Answer: A ✓ checked by 4AB · confidence medium

The source book printed D; on checking, A is correct — see the explanation.

Book printed (d).

Explanation
Steady state for C₂H₅: radicals are formed at a rate ∝ I and removed in pairs (rate ∝ [C₂H₅]²); the product-forming step therefore runs at a rate proportional to I (a).

Study loop for Chemical Kinetics

1. Practise the PYQsPrevious-year questions, with answers

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