The ${ }^{\mathrm{1}} \mathrm{H ~ NMR}$ spectrum of a dilute solution of a mixture of acetone and dichloromethane in $\mathrm{CDCl}_{3}$ exhibits two singlet of $\mathrm{1}: \mathrm{1}$ intensity. Molar ratio of acetone to dichloromethane in the solution is
(a)$3: 1$
(b)$1: 3$
(c)$1: 1$
(d)$1: 2$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Acetone has 6 H per molecule, CH₂Cl₂ has 2; equal integrals mean three times as many CH₂Cl₂ molecules — acetone : CH₂Cl₂ = 1 : 3.