Q27 · CSIR-NET Chemistry, June 2016

Paper: CSIR-NET June 2016 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Easy

Correct combination for $\pi$ and $\pi^{*}$ orbitals in $\mathrm{B_2}$ molecule is

(a)$\pi$: Gerade, $\pi^{*}$: Ungerade

(b)$\pi$: Ungerade, $\pi^{*}$: Gerade

(c)$\pi$: Gerade, $\pi^{*}$: Gerade

(d)$\pi$: Ungerade, $\pi^{*}$: Ungerade

Answer

Answer: B ✓ checked by 4AB · confidence high

Explanation

For a homonuclear diatomic the bonding π orbital is π_u (ungerade) and the antibonding π* is π_g (gerade).

Study loop for Chemical Bonding

1. Practise the PYQsPrevious-year questions, with answers

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