Q48 · CSIR-NET Chemistry, June 2021

Paper: CSIR-NET June 2021 · Subject: Physical Chemistry · Chapter: Surface Chemistry · Topic: Adsorption Isotherms · Marks: 2 · Difficulty: Medium

In a Langmuir-type adsorption, a solid adsorbs 0.25 mg of a gas when the pressure of the gas is 50 bar and 0.2 mg of the gas at 20 bar pressure. The percentage of surface coverage at 50 bar is close to:
(a)75
(b)38
(c)57
(d)83
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
0.25/0.20 = [50K/(1+50K)]/[20K/(1+20K)] gives K = 0.1 bar⁻¹; θ(50 bar) = 5/6 ≈ 83 % (d).

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