Liquid A has half the surface tension and twice the density of liquid B at $30^{\circ} \mathrm{C}$. The contact angles of A and B are the same. If A rises 10 cm in a capillary, then the rise (in cm ) of liquid B in the same capillary at the same temperature will be equal to
(a)60
(b)10
(c)40
(d)20
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
h ∝ γ/ρ: h_A/h_B = (½)/(2) = ¼, so h_B = 4 × 10 = 40 cm (c).