ABC26GN0549 · H.C.F. and L.C.M. of Numbers

Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: 2007 · Marks: · Difficulty:

A number less than 500, when divided by 4, 5, 6, 7 leaves remainder 1 in each case. The number is
(a)211
(b)420
(c)421
(d)441
Answer
Answer (as printed): C
Explanation
L.C.M. of 4, 5, 6, $7=420$. $$\therefore \quad \text { Required number }=420+1=421 .$$

Explanation as extracted from the printed page; notation may be imperfect.

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