The value of $\frac{(0.06)^{2}+(0.47)^{2}+(0.079)^{2}}{(0.006)^{2}+(0.047)^{2}+(0.0079)^{2}}$ is
(a)0.1
(b)10
(c)100
(d)1000
Answer
Answer (as printed): C
Explanation
Given expression $=\frac{a^{2}+b^{2}+c^{2}}{\left(\frac{a}{10}\right)^{2}+\left(\frac{b}{10}\right)^{2}+\left(\frac{c}{10}\right)^{2}}$, where $a=0.06, b=0.47$ and $c=0.079$. $$=\frac{100\left(a^{2}+b^{2}+c^{2}\right)}{\left(a^{2}+b^{2}+c^{2}\right)}=100 .$$
Explanation as extracted from the printed page; notation may be imperfect.