$\frac{(4.53-3.07)^{2}}{(3.07-2.15)(2.15-4.53)}+\frac{(3.07-2.15)^{2}}{(2.15-4.53)(4.53-3.07)}$ $$+\frac{(2.15-4.53)^{2}}{(4.53-3.07)(3.07-2.15)}$$ is simplified to
(a)0
(b)1
(c)2
(d)3
Answer
Answer (as printed): D
Explanation
Given expression $$\begin{aligned} & =\frac{(4.53-3.07)^{3}+(3.07-2.15)^{3}+(2.15-4.53)^{3}}{(4.53-3.07)(3.07-2.15)(2.15-4.53)} \\ & =\frac{a^{3}+b^{3}+c^{3}}{a b c}=\frac{3 a b c}{a b c}=3 . \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.